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a 2 2A I - Simplify 2 √
3 4 √ 3 − √ 27 - Find the Conjugate of 3
2I - 2 I 1 3I
Solution - Rotatin Transformation
of Vector - Simply 2 3I 4.
Use Caltech - 4 9𝑖 2 4 − 3𝑖
5 − 3𝑖 2𝑖 1 7𝑖 - I 6 I 7 I 8
I 9 I 2 I 3 - Z 1 Isinx 1 Isinx Then
Modulus Z - 4 I 2
8I - 4 5I Z
1 I - Re-Express 2I
and I - 5 Pi by Vy
4 ZZ2 - 5.3I
- Product of
1 4I and 2 3I - Complex Number
Quadrant
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