Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.
Meara covers streaming service news for CNET. She graduated from the University of Texas at Austin with a degree in journalism. When she's not writing, she likes to dote over her cat, sip black coffee ...
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